College Algebra problem?

Find a cubic equation with integral coefficients that has the given roots.

4+i sqrt3 all over 2 and -1

Comments

  • if 4 + i√3 over 2 is a root, so is 4 - i√3 over 2

    The sum of these is 8/2 = 16/4

    the product is 16 - i^2 (3) over 4 = (16 + 3) / 4 = 19/4

    so the quadratic giving those roots is (4x² - 16x + 19)

    [since the sum of the roots of ax^2 + bx + c is -b/a, and the product is c/a]

    and the -1 comes from a factor of (x + 1)

    so multiply (x + 1)(4x² - 16x + 19)

  • im in 8th grade algebra so im no help

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