The only that you can do with this is simplify it, because the radical it's on top, but if it is on the bottom you have to multiply the whole fraction by the radical that is on bottom.
The method is called the triangle if the numbers are visible by the denominator you can reduce it. Like this case.
x= -6+-2(root3)/12
( 6 and 2 are visible by 12)
x=-3+-(root3)/6 but if you want to reduce it more you can separe them like this.
x= -3/6 +-(root3)/6
x=-1/2 +-(root3)/6 but most common is x=-3+-(root3)/6
Convert the radical to it's equivalent decimal number and do the division. If the value under the radical is not a perfect square, it's an irrational number and it will be much more convenient to use a calculator than to manually extract the square root and do the long division manually.
x = (-6±2â3)/12 = -2±â3/6
â3 is an irrational number approximately equal to 1.732
Comments
I guess it is the quadratic formula. right?
The only that you can do with this is simplify it, because the radical it's on top, but if it is on the bottom you have to multiply the whole fraction by the radical that is on bottom.
The method is called the triangle if the numbers are visible by the denominator you can reduce it. Like this case.
x= -6+-2(root3)/12
( 6 and 2 are visible by 12)
x=-3+-(root3)/6 but if you want to reduce it more you can separe them like this.
x= -3/6 +-(root3)/6
x=-1/2 +-(root3)/6 but most common is x=-3+-(root3)/6
I hope you understand me
Convert the radical to it's equivalent decimal number and do the division. If the value under the radical is not a perfect square, it's an irrational number and it will be much more convenient to use a calculator than to manually extract the square root and do the long division manually.
x = (-6±2â3)/12 = -2±â3/6
â3 is an irrational number approximately equal to 1.732
-2±â3/6 â -2 ± 1.732/6 â -2 ± 0.289 â -2.289, -1.711
Well, you can factor out a 2.
-3 +/- sqrt(3) / 6
In that case, you have to physically calculate the root, which would roughly be 1.73, and then divide that.
I hope this information was very helpful.