Como resolver esses produtos notáveis com fração?

(x/2 + 2)³

e

(- 2/3x + 1/3) . (2/3x + 1/3)

PRECISO DOS CÁLCULOS ORGANIZADOS E BEM DESENVOLVIDOS!!

Comments

  • (a + b)³ = a³ + 3a²b + 3ab² + b³

    (a + b)(a – b) = a² - b²

    (x/2 + 2)³ = (x/2)³ + 3 . (x/2)² . 2 + 3 . (x/2) . 2² + 2³

    (x/2 + 2)³ = x³/8 + 3 . x²/4 . 2 + 3 . x/2 . 4 + 8

    (x/2 + 2)³ = x³/8 + 6x²/4 + 12x/2 + 8 --> simplificando

    (x/2 + 2)³ = x³/8 + 3x²/2 + 6x + 8 --> mmc (2, 8) = 8

    (x/2 + 2)³ = x³ + 12x² + 48x + 64 / 8

    (- 2/3x + 1/3) . (2/3x + 1/3) --> organizando

    (1/3 + 2/3x) (1/3 - 2/3x) = (1/3)² - (2/3x)²

    (1/3 + 2/3x) (1/3 - 2/3x) = 1/9 - 4/9x

    Espero ter ajudadoo!

  • (x/2 + 2)³ = (x/2)³ + 3. (x/2)².2 + 3. (x/2) . 2² + 2² = x³/8 + 6x²/4 + 12x/2 +4 = x³/8+3x²/2+6x+4

    (- 2/3x + 1/3) . (2/3x + 1/3) = - (2/3x-1/3)(2/3x+1/3) = -((2/3x)²-(1/3)² = -(4/9x² -1/9) = -4/9x² + 1/9

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