how do you solve lim (1-tanx)/(sinx-cosx) as x approaches pie divided by 4?

thanks in advance! :D

Comments

  • Since the numerator and denominator approach 0, use L'Hopital's rule and take the derivatives of the numerator and denominator. Also, it's pi, not pie.

    lim (1 - tanx)/(sinx - cosx) =

    x-> pi/4

    lim -sec^2x/(cosx + sinx) = -(√2)^2/(√2/2 + √2/2) = -2/(√2) = -√2

    x-> pi/4

Sign In or Register to comment.