¿como resolver problema de 3x3? Doy 5 estrellas!!!!?

2x+y+2z=-1

x-y+z=-8

3x+y-2z=1

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  • 2x+y+2z=-1

    x-y+z=-8

    = 3x+3z=-9

    -2(x-y+z=-8)

    3x+y-2z=1

    = x+3y=17

    2x+y+2z=-1

    3x+y-2z=1

    =5x+2y=0

    y= 2.5x

    Sustituyendo

    x+3(2.5x)=17

    x=2

    Por tanto y= 2.5x y=2.5(2) y=5

    Sustituyendo de nuevo

    x-y+z=-8

    (2)-(5)+z=-8

    Por tanto z= -11

    x=2

    y=5

    z= -11

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