You need to get the top and bottom to have similar terms. Since the left and right side of the Numerator's Minus sign have a common factor (a+b). You can rewrite it like this:
x(a+b)-2(a+b) = (x-2)(a+b)
In the denominator, you can simplify -(2-x) by multiplying the inside by -1
Comments
You need to get the top and bottom to have similar terms. Since the left and right side of the Numerator's Minus sign have a common factor (a+b). You can rewrite it like this:
x(a+b)-2(a+b) = (x-2)(a+b)
In the denominator, you can simplify -(2-x) by multiplying the inside by -1
(-2+x)
which when moved around is
(x-2)
So now you have
(x-2)(a+b) OVER (x-2)
and simplified to
(a+b) OVER 1
In the numerator, factor out the (a+b) to get:
(a+b)(x-2)/-(2-x)
Factor out a -1 from the (x-2) to get:
-(-x+2)(a+b)/-(2-x)
Notice that -(2-x) is now in the numerator and the denominator, so it cancels out. Your answer is a+b
You can take out the (a + b) out of the numerator to get:
(x - 2)(a + b) / -(2 - x)
But the denominator is the same as:
(x - 2)
So you actually have:
(x - 2)(a + b) / (x - 2)
Which reduces to:
(a + b)
x(a+b) - 2(a+b) first factor out (a+b) this leaves
(a+b)(x-2) now recognize that -(2-x) is the same as -2+x or x-2
so (a+b)(x-2) divided by (x-2) gives
(a+b)
a+b is d ans