Math Problem???????????????????????????
I need the answer to this math problem because I honestly don't know how to do it and nobody is willing to help me. Problem: During an evening out, Dean paid a cab driver $20. He then spent $25 on dinner and half of his remaining money on a painting. He bought an umbrella for $23.75 and had $42.15 left. How much money did Dean have at the beginning of the weekend?
Comments
Let total amount be x.
Cab - $20
Dinner - $25
Remaining Amount- (x-45)
Hlf of this amount was spent on painitng. So, net cash in hand is (x-45)/2.
out of this cash in hand, he has gt umbrella for 23.75, and balance cash is 42.15.
so, (x-45)/2=23.75+42.15
(x-45)/2=65.9
x-45=131.8
x=176.8
Amount Dean had at the beginning of the weekend = $176.8
Suppose he had X dollar at the beginning of the weekend.
He paid a cab $20, so after paying he's got X-20 left
The dinner cost $25. Left X-20-25 = X-45
He bought a painting, which cost half of what he had, so after paying for the painting, he's got the other half: (X-45)/2
After the umbrella: (X-45)/2 - 23.75, apparently this equals 42.15
So solve: (X-45)/2 - 23.75 = 42.15 ==> (X-45)/2 = 42.15 + 23.75 = 65.90 ==>
X-45 = 65.90 * 2 = 131.80 ==> X = 131.80 +45.00 = 176.80