(4x^2-22)(x^2-16) ?
the ^ means power
(a+b)(c+d) = ac+ad+bc+bd
So in this case:
(4x^2-22)(x^2-16)= 4x^4 -22x^2 -64x^2 +352 = 4x^4 -86x^2 +352
FOIL the left side, and you get:
4x^4 - 86x^2 +352 = 64x^4
subtract everything to the right side:
0=60x^4 + 86x^2 -352
divide by 2 to make it easier to look at.
0=30x^4 + 43 x^2 - 176
Treat x^2 like x for now, and you get 30x^2 + 43x -176
Using the quadratic formula, you will get (-43+- 151.56)/60
If you only want real solutions use x^2 = (-43 + 151.56)/60
x^2= about 1.8
x= +- 1.34
That is an UGLY problem for 9th grade math...sheesh
Phyllis,
Open the brackets and simplify
4X^2*(X^2-16)-22*(X^2-16) = 64X^4
4X^4-64X^2-22X^2+352 = 64X^4
-60X^4-86X^2+352 = 0 (64X^4 transferred to left hand side)
60X^4+86X^2-352 = 0 (multiply both side by -1)
Now use your skill to factor this, I am sure you know this.
Compare each bracket with 0 and get X values.
[email protected]
http://www.wolframalpha.com/input/?i=%284x^2-22%29...
Comments
(a+b)(c+d) = ac+ad+bc+bd
So in this case:
(4x^2-22)(x^2-16)= 4x^4 -22x^2 -64x^2 +352 = 4x^4 -86x^2 +352
FOIL the left side, and you get:
4x^4 - 86x^2 +352 = 64x^4
subtract everything to the right side:
0=60x^4 + 86x^2 -352
divide by 2 to make it easier to look at.
0=30x^4 + 43 x^2 - 176
Treat x^2 like x for now, and you get 30x^2 + 43x -176
Using the quadratic formula, you will get (-43+- 151.56)/60
If you only want real solutions use x^2 = (-43 + 151.56)/60
x^2= about 1.8
x= +- 1.34
That is an UGLY problem for 9th grade math...sheesh
Phyllis,
Open the brackets and simplify
4X^2*(X^2-16)-22*(X^2-16) = 64X^4
4X^4-64X^2-22X^2+352 = 64X^4
-60X^4-86X^2+352 = 0 (64X^4 transferred to left hand side)
60X^4+86X^2-352 = 0 (multiply both side by -1)
Now use your skill to factor this, I am sure you know this.
Compare each bracket with 0 and get X values.
[email protected]
http://www.wolframalpha.com/input/?i=%284x^2-22%29...