Find the value of a, b nd c.
a b c=3
4a 2b c=7
9a 3b c=12
with solution
a b c=3 a b c = 3 a b c = 3
4a 2b c=7 ~ -2b -3c =-5 ~ 2b 3c =5
9a 3b c=12 -6b -8c =-15 c =0
2b=5, b=2.5,
a=3-2.5=0.5
(a, b, c)=(0.5, 2.5, 0)
if i suppose the operator between these is +
then substract equation 2 from 3
9a+3b+c=12
4a+2b+c=7
------------------
5a+b=5------------------(4)
substract equation 1 from 3
a+ b+ c=3
------------
8a+2b=9----------(5)
sub 2*equation(4) from 5
10a+2b=10
8a+2b=9
2a=1
=>a=.5
b=2.5
c=0
solve the two obtained
Are 4a,2b and c multiplying?
i think you've made a mistake.what is the sign
Comments
a b c=3 a b c = 3 a b c = 3
4a 2b c=7 ~ -2b -3c =-5 ~ 2b 3c =5
9a 3b c=12 -6b -8c =-15 c =0
2b=5, b=2.5,
a=3-2.5=0.5
(a, b, c)=(0.5, 2.5, 0)
if i suppose the operator between these is +
then substract equation 2 from 3
9a+3b+c=12
4a+2b+c=7
------------------
5a+b=5------------------(4)
substract equation 1 from 3
9a+3b+c=12
a+ b+ c=3
------------
8a+2b=9----------(5)
sub 2*equation(4) from 5
10a+2b=10
8a+2b=9
------------
2a=1
=>a=.5
b=2.5
c=0
solve the two obtained
Are 4a,2b and c multiplying?
i think you've made a mistake.what is the sign