1/x is the "reciprocal" of x. If x is a fraction, you can get the reciprocal of x by flipping it, e.g. if x = 2/3, then 1/x = 3/2. 1/1/x ("the reciprocal of the reciprocal of x") just means that you flip x twice, and you'll get back the same number, so 1/1/x = x.
first rearrange to get the sq. root on my own so root (3x+a million) = (x-a million) to get rid of the sq. root, sq. the two facets so ( (sq. root of 3x+a million) ) ^ 2 = 3x + a million so 3x+a million = (x-a million)^2 then 3x + a million = x^2 -2x + a million set = to 0 0 = x^2 - 5x 0 = x ( x - 5) so x = 0 or 5, yet continuously plug back into the unique equation whilst dealing with sq. roots to be certain no damaging roots and fake solutions. once you plug the solutions back in you come across that 0 does not artwork. so purely x= 5 is the respond.
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Im guessing?:
When you divide 1 by 1/x = x
(1)(x/1)=x
so
x+8=-19
subtract 8 from both sides
1/x is the "reciprocal" of x. If x is a fraction, you can get the reciprocal of x by flipping it, e.g. if x = 2/3, then 1/x = 3/2. 1/1/x ("the reciprocal of the reciprocal of x") just means that you flip x twice, and you'll get back the same number, so 1/1/x = x.
first rearrange to get the sq. root on my own so root (3x+a million) = (x-a million) to get rid of the sq. root, sq. the two facets so ( (sq. root of 3x+a million) ) ^ 2 = 3x + a million so 3x+a million = (x-a million)^2 then 3x + a million = x^2 -2x + a million set = to 0 0 = x^2 - 5x 0 = x ( x - 5) so x = 0 or 5, yet continuously plug back into the unique equation whilst dealing with sq. roots to be certain no damaging roots and fake solutions. once you plug the solutions back in you come across that 0 does not artwork. so purely x= 5 is the respond.