Algebra world problem.?
Given that y varies directly as the square of x and inversely as z, and y = 2 when x = 5 and z = 100. What is y when x = 3 and z = 4?
Given that y varies directly as the square of x and inversely as z, and y = 2 when x = 5 and z = 100. What is y when x = 3 and z = 4?
Comments
y=kx^2/z
2=(5^2)k/100
2=25k/100
2=k/4
k=8
y=8x^2/z
y=9*8/4
y=18
I'm pretty sure that's it, comment on this if you think this is unclear.