Algebra world problem.?

Given that y varies directly as the square of x and inversely as z, and y = 2 when x = 5 and z = 100. What is y when x = 3 and z = 4?

Comments

  • y=kx^2/z

    2=(5^2)k/100

    2=25k/100

    2=k/4

    k=8

    y=8x^2/z

    y=9*8/4

    y=18

    I'm pretty sure that's it, comment on this if you think this is unclear.

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