[Present Age]
Father is 3 times as old as his son
[14 Years later]
Father is 2 times as old as his son
What is the father's age?
Two equations with two unknowns.
Let x be the father's current age.
Let y be the son's current age.
Clearly, x = 2y
14 years ago, father's age was (x-14) and son's (y-14)
You do the rest of it.
Let's make a couple of equations to solve this puzzle.
Let's make the son;s present age "s", and the father's present age "f"
3s = f
(s + 14) * 2 = f + 14
Solving both for the fathers age and simplifying, we get:
and
2s + 14 = f
Because the first parts of these equations both equal f, we can make them equal to each other, so;
3s = 2s + 14
Solving, we get the son's age;
s = 14
Now we plug that back into one of the equations we solved for the the father's age;
14 * 3 = 42
14 * 2 + 14 = 42
So, the father is currently 42.
Let x = the son's current age
then 3x = the father's current age
and x+14 = the son's age in 14 years
and 3x+14 = the father's age in 14 years.
3x + 14 = 2(x+14)
3x+14=2x+28
x=14
3*14=42
y = father's age present day, x = son's age present day
Present day:
y = 3x
14 years later we're told the equation becomes this:
y + 14 = 2(x + 14)
y + 14 = 2x + 28
y = 2x +14
Now we substitute y = 3x back in:
3x = 2x + 14
3 = 2 + (14/x)
1 = 14/x
1x = 14
x = 14
Now to find the father's age we multiply the son's age by 3:
y = 3 x 14
y = 42
Let father's age be=x
Let son's age be=y
therefore, a.t.q, x=3y - eq 1
also, x+14=2(y+14)
therefore, x+14=2y+28
x-2y=28-14 ie x-2y=14- eq 2
frm eq 1 nd 2, obtain the value of x ie fatehr's age which is 42, age of son=14 u can verify it if u want...
f = 3s
f+14 = 2(s+14)
f+14 = 2s+28; substitute in f = 3s
3s + 14 = 2s + 28
subtract 2s from both sides
s+14=28; s = 14
==============
substitute this in f = 3s to get father's age
f = 3(14) = 42
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Comments
Two equations with two unknowns.
Let x be the father's current age.
Let y be the son's current age.
Clearly, x = 2y
14 years ago, father's age was (x-14) and son's (y-14)
You do the rest of it.
Let's make a couple of equations to solve this puzzle.
Let's make the son;s present age "s", and the father's present age "f"
3s = f
(s + 14) * 2 = f + 14
Solving both for the fathers age and simplifying, we get:
3s = f
and
2s + 14 = f
Because the first parts of these equations both equal f, we can make them equal to each other, so;
3s = 2s + 14
Solving, we get the son's age;
s = 14
Now we plug that back into one of the equations we solved for the the father's age;
14 * 3 = 42
14 * 2 + 14 = 42
So, the father is currently 42.
Let x = the son's current age
then 3x = the father's current age
and x+14 = the son's age in 14 years
and 3x+14 = the father's age in 14 years.
3x + 14 = 2(x+14)
3x+14=2x+28
x=14
3*14=42
y = father's age present day, x = son's age present day
Present day:
y = 3x
14 years later we're told the equation becomes this:
y + 14 = 2(x + 14)
y + 14 = 2x + 28
y = 2x +14
Now we substitute y = 3x back in:
3x = 2x + 14
3 = 2 + (14/x)
1 = 14/x
1x = 14
x = 14
Now to find the father's age we multiply the son's age by 3:
y = 3x
y = 3 x 14
y = 42
Let father's age be=x
Let son's age be=y
therefore, a.t.q, x=3y - eq 1
also, x+14=2(y+14)
therefore, x+14=2y+28
x-2y=28-14 ie x-2y=14- eq 2
frm eq 1 nd 2, obtain the value of x ie fatehr's age which is 42, age of son=14 u can verify it if u want...
f = 3s
f+14 = 2(s+14)
f+14 = 2s+28; substitute in f = 3s
3s + 14 = 2s + 28
subtract 2s from both sides
s+14=28; s = 14
==============
substitute this in f = 3s to get father's age
f = 3(14) = 42
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