how do you do these 3 algebra problems?

solve for x show all work these are the problem i can't do

1. (x/a)=b+x

2. x^2+10x=-24

3. c(x+2)+ax=4

Update:

i also need help on this problem (x^3-4x)/(x^3-4x^2+4x)

Comments

  • 1. (x/a)=b+x, multiply everything by a

    x=ab+ax, subtract ax from both sides

    x-ax=ab, factor out an x on the LHS

    x(1-a)=ab, divide by (1-a)

    x=ab/(1-a)

    2.x^2+10x=-24, set equal to zero by addding 24 to each side

    x^2+10x+24=0, factor

    (x+4)(x+6)=0

    x=-4 or x=-6

    3.c(x+2)+ax=4, distribute the c

    cx+2c+ax=4, subtract 2c from each side

    cx+ax=4-2c, factor out an x from the LHS

    x(c+a)=4-2c, divide by (c+a)

    x=(4-2c)/(c+a)

  • 1. im not sure

    2. x^2 + 10x +24 = 0

    (x+6)(x+4)

    x = -6, x = -4

    3.cx + 2c + ax =4

    cx + ax = 4-2c

    x(c+a)=4 -2c

    x = (4 -2c)/(c+a)

  • 2) add 24 to both sides . factor . (x+6)(x+4) x=-4, -6

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