3y+2 / 5 - y-3 / 10 = -4
[(3y + 2)/5] - (y - 3)/10 = - 4
clear denominators...multiply by 10...
2(3y + 2) - (y - 3) = - 40
6y + 4 - y + 3 = - 40
5y = - 47
y = (- 47)/5
check
Σ
Find a number that all the denominators go into (5 and 10 both go into 10), so multiply everything by 10:
10(3y + 2) / 5 - 10(y - 3) / 10 = 10(-4)
Simplify the fractions:
2(3y + 2) - 1(y - 3) = 10(-4)
Expand the brackets:
6y + 4 - y + 3 = -40
Combine the like terms:
5y + 7 = -40
Subtract 7 from both sides:
5y = -47
Divide both sides by 5:
y = -47/5
Brackets should really be used.
(3y + 2) / 5 - (y - 3) / 10 = - 4
y = - 47/5
Comments
[(3y + 2)/5] - (y - 3)/10 = - 4
clear denominators...multiply by 10...
2(3y + 2) - (y - 3) = - 40
6y + 4 - y + 3 = - 40
5y = - 47
y = (- 47)/5
check
Σ
Find a number that all the denominators go into (5 and 10 both go into 10), so multiply everything by 10:
10(3y + 2) / 5 - 10(y - 3) / 10 = 10(-4)
Simplify the fractions:
2(3y + 2) - 1(y - 3) = 10(-4)
Expand the brackets:
6y + 4 - y + 3 = -40
Combine the like terms:
5y + 7 = -40
Subtract 7 from both sides:
5y = -47
Divide both sides by 5:
y = -47/5
Brackets should really be used.
(3y + 2) / 5 - (y - 3) / 10 = - 4
6y + 4 - y + 3 = - 40
5y = - 47
y = - 47/5