Quick algabra Help. Please!?

Comments

• pi-r-squared

  June 2021

  Hi,

  Q1) Find B union D.

  B: {−2, −1, 1, 4, 7, 12}

  {numbers divisible by 3 from 1 to 15}

  {12}

  {−2, −1, 1, 3, 4, 7, 12}

  {−2, −1, 1, 3, 4, 6, 7, 9, 12, 15} <==ANSWER

  { }

  Q2) Find C intersection D.

  C: {3, 6, 9, 12, 15, 18}

  {numbers divisible by 2 from 1 to 20}

  {2, 4, 6, 8, 10, 12, 14, 16, 18, 20}

  {6, 12, 18} <==ANSWER

  {2, 3, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20}

  { }

  I hope that helps!! :-)
• a-square

  June 2021

  1) Your answer is the set that has all the elements from both sets B and D

  {−2, −1, 1, 3, 4, 6, 7, 9, 12, 15}

  2) You answer is the set that has all the elements that sets C and D have in common

  {6, 12, 18}
• bill-brasky

  June 2021

  set D is (3,6,9,12,15)

  so combining both B and D in union means combining all of their elements into one set. we get:

  {-2, -1, 1, 3, 4, 6, 7, 9, 12, 15}

  Intersection means certain elements appear in both sets. Numbers divisible by 2 is simply the even numbers from 1 to 20

  {6,12,18}
• anonymous

  June 2021

  1) B = {-2,-1,1,4,7,12}

  D = {3,6,9,12,15}

  B U D = {-2,-1,1,3,4,6,7,9,12,15}

  2) C = {3,6,9,12,15,18}

  D = {2,4,6,8,10,12,14,16,18,20}

  C U D = {2,3,4,6,8,9,10,12,14,15,16,18,20}