How do you solve this algebra problem?

4x + 8 - 2x - 1 < 3(x+2) -x

______________________

....4.........3....

(To clarify, it's 4x+8 divided by 4 minus 2x-1 divided by 3 is less than 3(x+2) minus x.)

Comments

  • First of all, make it the same denominator at the left side:

    multiply(4x + 8)/4 by 3 and (2x -1)/3 by 4.

    Then simplify it

    you should get (x+7)/3 < 2x+6

    make it (x+7)/3 < 2x+6/1 and cross multiply

    Which give you x+7 < 6x+18

    Bring x to one side, number to the other

    Final answer is negative fraction.

    Correct me if I'm wrong.

  • 4x + 8/4 reduces to

    x + 2

    2x - 1 over 3 will not reduce (so we multiply by three)

    3(x + 2) - x = 2x + 6

    so that

    x + 2 -{2x-1/3} < 2x + 6

    3x + 6 -2x + 1 < 6x + 18

    5x + 7 < 6x +18

    0 < X + 11

    -11 < X

    I guess - sorry I am so sleepy

  • (4x+8)/4 - (2x-1)/3 < 3(x+2)-1 simplyfing we get:

    x+2 -(2x-1)/3 < 3x +5 now multiply both sides by 3:

    = 3x + 6 -2x +1 < 9x +15

    = x + 7 < 9x + 15 now subtract x from both sides

    = 7 < 8x +15 now subtract 15 from both sides

    = -8 < 8x or -1 <x

    x>-1

  • (4x + 8 )/4 - (2x-1)/3 < 3(x+2)-x

    (4x + 8)/4 = x + 2

    x+2 - (2x-1)/3 < 3(x+2)-x || ( )*3

    3x + 6 - (2x-1) < 9(x+2)-3x

    3x -2x + 6+1 < 9x+18 -3x

    3x-2x-9x+3x <18-6-1

    -5x <11

    x> - 2,2

  • x+2-(2/3)x-(1/3)<3x+6-x...............first distribute everything

    (1/3)x+(5/3)<2x+6.......................combine like terms

    (5/3)<(5/3)x+6............................get all of the x's on one side

    -(13/3)<(5/3)x.............................get all of the constants on one side

    -(13/5)<x....................................divide both sides by 5/3 to get x by itself

    so, x>-13/5 or x>-2.6 is the final answer!!!

  • Sorry mate; it is far too convoluted to commit time to deciphering

    Re-express and I will help. Hint, use more brackets, parentheses ...

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