JC are you sure?
Use factoring decomposition. Split -5x into -6x and x since -6 and +1 yields the product of -6 and the sum of -5...
2x² - 6x + x - 3
Factor like terms to get..
(2x² - 6x) + (x - 3)
= 2x(x - 3) + 1(x - 3)
Finally, we have..
(x - 3)(2x + 1) [Group the common factors of x - 3 and collect the terms!]
I hope this helps!
Multiply 2 by -3. That give us -6.
Find two numbers who when multiplied give us -6 but at the same time also adds up to -5.
-6 and +1 are the only integers that work.
Now, divide 2 by each of these numbers.
2 / -6 = 1 / -3
2 / 1 = 2 / 1
Then use these expressions to write the newfactored expression.
(x - 3) (2x + 1)
(2x - 1) (x - 2)
If the question is 2x^2 - 5x -3 = 0
then x = 1/2 or 2
(2x+1)(x-3)
use the quadratic formula
Comments
Use factoring decomposition. Split -5x into -6x and x since -6 and +1 yields the product of -6 and the sum of -5...
2x² - 6x + x - 3
Factor like terms to get..
(2x² - 6x) + (x - 3)
= 2x(x - 3) + 1(x - 3)
Finally, we have..
(x - 3)(2x + 1) [Group the common factors of x - 3 and collect the terms!]
I hope this helps!
Multiply 2 by -3. That give us -6.
Find two numbers who when multiplied give us -6 but at the same time also adds up to -5.
-6 and +1 are the only integers that work.
Now, divide 2 by each of these numbers.
2 / -6 = 1 / -3
2 / 1 = 2 / 1
Then use these expressions to write the newfactored expression.
(x - 3) (2x + 1)
(2x - 1) (x - 2)
If the question is 2x^2 - 5x -3 = 0
then x = 1/2 or 2
(2x+1)(x-3)
use the quadratic formula