You know the first numbers will be (x____) multiplied by (5x____) because 5 is a prime number and you can't put anything else. Then for the two end numbers, what times what is 10? well there's 5x2 so the middle has to be a negative so the bigger number which is the 5 will be negative. so its (5x-5) (x-2) to check your answer, you just multiply the fronts first so its 5.1, and then -10-5 which is -15 and multiply the back which is 10. It's correct!
First, 5 is a factor of all 3, therefore you can factor out a 5 to get 5(x^2-3x+2). Then, we need two numbers that multiply together to make 2 and that when we add them, we get -3. -2 and -1 will work wonderfully. Therefore, we get 5(x-2)(x-1). Hope it helps!!!
If you really struggle, take Applied, and succeed. In grade 12, you can take data management, which allows you to take math in university. It's better you do well in applied than poorly in academic. Never choose your classes based on prestige. Best of luck!
it is factored already, all you have to do is put it in "decending order" which means the "x" which has the highest POWER goes first, then the next smalleset, and then the number which has no exponents behind it will be last.
Comments
5*(x^2-3x+2)
5*(x-2)(x-1)
Since the constant is positive, the 2 signs need to be the same.
Since the x-term is negative, the signs need to be negative
When you add the numbers, you need to get -3 and when you multiply them you need to get +2.
You cna use these basic concepts to factor most quaratics.
You know the first numbers will be (x____) multiplied by (5x____) because 5 is a prime number and you can't put anything else. Then for the two end numbers, what times what is 10? well there's 5x2 so the middle has to be a negative so the bigger number which is the 5 will be negative. so its (5x-5) (x-2) to check your answer, you just multiply the fronts first so its 5.1, and then -10-5 which is -15 and multiply the back which is 10. It's correct!
1st factor is 5:
= (5x² - 15x + 10)/5
= x² - 3x + 2
2nd factor is x - 1:
= (x² - 3x + 2)/(x - 1)
= x - 2
At this point, x - 2 cannot be further factored.
Therefore the factors are: 5, x - 1 and x - 2 and they can be expressed in the following manner:
= 5(x - 1)(x - 2)
First, 5 is a factor of all 3, therefore you can factor out a 5 to get 5(x^2-3x+2). Then, we need two numbers that multiply together to make 2 and that when we add them, we get -3. -2 and -1 will work wonderfully. Therefore, we get 5(x-2)(x-1). Hope it helps!!!
5X^2 - 15 X +10 = 5*(x²-3x+2) = 5*(x-1)*(x-2)
take 5 out the front
so 5 (x^2 - 3x + 2)
now with the polynomial bit you find the factors, which would be -1 and -2 because they add to -3 and multiply to 2
so factorising
5(x-1)(x-2) is your answer
If you really struggle, take Applied, and succeed. In grade 12, you can take data management, which allows you to take math in university. It's better you do well in applied than poorly in academic. Never choose your classes based on prestige. Best of luck!
first divide through by 5
x^2 - 3x + 2
(x-1)(x-2)
it is factored already, all you have to do is put it in "decending order" which means the "x" which has the highest POWER goes first, then the next smalleset, and then the number which has no exponents behind it will be last.
so it will be exactly how you have it
5x^2 - 15x +10
(5X - 5)(x - 2) is your answer.