How do i turn 2x+y=5 into slope intercept form?

im very confused, how do i turn 2x+y=5 into slope intercept form

Comments

  • Y=2x-5 is the answer

  • Subtract 2x from both sides making =

    Y=-2x+5

  • Subtract 2x and put it before 5 so then you have y=2x-5

  • Adequate i'm not a high institution maths teacher, so it may pay to verify with any one else! However at the time of me typing I seem to be all you might have (confidently anybody else will come alongside!), so right here goes... For your graph, put a dot at 2,2 (ie, 2 squares throughout and a pair of squares up). Put an additional dot at 7 on the y-axis. Become a member of them. You are going to see that the road goes down 5 squares for each 2 squares it goes throughout to the correct. Considering it goes DOWN 5 squares it is "-5". When you consider that it goes 2 to the correct it is "2". (Left would be "-2"). So you have the "-5/2" phase. The +7 is solely where it intercepts the y-axis. And an intercept equation is what you need. So put "y=" on the start and "+7" on the tip. Now you've got "y=-5/2+7". I'm sure there may be a better explanation!

  • subtract 2x. y=-2x+5 see, slope intercept formula is y=mx+b which means.

    your y coordinate= slope(x coordinate)+ y intercept.

  • subtract 2x...y=-2x+5

  • subtract 2x from each side

  • Do inverse

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