colocadas a uma distancia de 70 cm no vacuo.
no livro as resposta e 110,2.10^-3 N
d = 70 cm = 0,7 m = 7.10^-1 m
F = ko.Q1.Q2/d²
F = 9.10^9.1.10^-6.6.10^-6/(7.10^-1)²
F = 54.10^-3/49.10^-2
F = 1,102.10^-3.10^2
F = 1,1.10^-1
F = 0,11 N
F= 9x10^9.1x10^-6.6x10^-6/ (7x10^-1)^2
F= 54x10^9+(-6)+(-6)=-3/49x10^-2
F= 54x10^-3/49x10^-2
F= 1,102x10^-3+(-2)=-5
F= 1,102x10^-5
F= 110,2x10^-5+2=-3
F= 110,2x10^-3
Comments
d = 70 cm = 0,7 m = 7.10^-1 m
F = ko.Q1.Q2/d²
F = 9.10^9.1.10^-6.6.10^-6/(7.10^-1)²
F = 54.10^-3/49.10^-2
F = 1,102.10^-3.10^2
F = 1,1.10^-1
F = 0,11 N
F= 9x10^9.1x10^-6.6x10^-6/ (7x10^-1)^2
F= 54x10^9+(-6)+(-6)=-3/49x10^-2
F= 54x10^-3/49x10^-2
F= 1,102x10^-3+(-2)=-5
F= 1,102x10^-5
F= 110,2x10^-5+2=-3
F= 110,2x10^-3