You will need to break the expression up into smaller pieces. To do this multiply the value of 2x^2 (2) against the value of -5y^2 (-5)
2 * -5 = -10
Factors of -10 = +-(1, 2, 5, 10)
From the list of factors find two numbers that when added together give 3 and when multiplied together give -10. 5 and -2 added together give 3 and multiplied together give -10 so rewrite these values back into the expression:
2x^2 + 5xy - 2xy - 5y^2
Now take out the HIGHEST common factor between the two sets of terms:
Comments
2x^2+3xy-5y^2=
=2x^2-2xy+5xy-5y^2=
=2x(x-y)+5y(x-y)=
=(x-y)(2x+5y)
You will need to break the expression up into smaller pieces. To do this multiply the value of 2x^2 (2) against the value of -5y^2 (-5)
2 * -5 = -10
Factors of -10 = +-(1, 2, 5, 10)
From the list of factors find two numbers that when added together give 3 and when multiplied together give -10. 5 and -2 added together give 3 and multiplied together give -10 so rewrite these values back into the expression:
2x^2 + 5xy - 2xy - 5y^2
Now take out the HIGHEST common factor between the two sets of terms:
x(2x + 5y) - y(2x + 5y)
Refactor it:
(x - y) (2x + 5y)
That is now fully factorised.
2x^2+5xy-2xy-5y^2
x(2x+5y)- y(2x+5y)
(2x+5y) (x-y)