How do i do this problem?
Read the following problem carefully and then answer the question asked.
The length of a rectangle is twice the width. The perimeter of the rectangle is 24 feet. What is the length of the rectangle?
Let x = the width of the rectangle.
Which let statement would you use for the length?
Comments
Let x = the width of the rectangle
and
Let y =the length of the rectangle
from the question
y =2x
perimeter =2(x+y) =24 feet
2(x+y) =24
x+y =24/2 =12
as y=2x
x+2x=12
3x =12
x =12/3 =4
y =2x =2*4 =8
width =x =4 feet
length =y =8 feet.
Since it's double you'll want the length to be 2x. This way you just times it by 2 once you know x
P = 2L+2W
Let x = the width of the rectangle
Let 2x = the length of the rectangle
2(2x) + 2(x) = 24
4x+2x=24
6x=24; divide by 6
x=4
2(4) = 8
Length = 8
Width = 4
Blessings
Let x = width of the rectangle
y= length of the rectangle.
According to the condition:
y = 2x ............... (1)
Now perimeter of the rectangle:
2y + 2x = 24
y + x = 12 ............(2)
Now substituting the value of y in eq.(2) we get:
2x + x = 12
3x = 12
x = 4 feet
From eq.(2)
y + 4 =12
y = 8 feet or y = 2x = 2*4 = 8 feet
Width = 4 feet
Length = 8 feet
Hope this helps:)
You can go around the rectangle and count that there are 6 lots of x. (1 for each end, 2 for each length)
So 6x=24
x = 24/6
if x is the width, then length is 2x.
perimeter is 2*length + 2*width = 24
24 = 2(2x) + 2(x)
24 = 4x + 2x
24 = 6x
x = 4
P=2a+2b
a=2b
P=2(2b)+2b
P=6b =24 feet
b=24/6=4feet
a=2b=8feet
L = 2W......(1)
2(L+W) = 24......(2)
Plug in (1) into (2),
2W+W = 24/2 = 12
W = 4
L = 2W = 8
Answer: The length is 8 ft.