Temp. Pressure and Volume problem.?

coolhomie9coolhomie9
in Science & Mathematics

A gas has a volume of 1.75L at -23 degrees celcius and a 150 kPa. At what Temp. will the gas occupy 1.30L at 210 kPa?

Finding temp is the only one I cant figure out i get a very small answer like .0038 i dont think it is correct.

Please help!

Comments

  • goaliemangoalieman

    Don't forget that Temperatures need to be in Kelvin.

    P1 * V1 / T1 = P2 * V2 / T2

    (150kPa) * (1.75L) / (-23 +273) = (210kPa) * (1.30L) / (T2 + 273)

    T2 = -13 degrees C

  • ebedsworthebedsworth

    Make sure you change the temperature to Kelvin and put it into the ideal gas equation. Hope this helps.

  • cobracobra

    PiVi/Ti=PfVf/Tf 23 degrees celcius+273k=296k

    150kPa*1.75L/296k=210kPa*1.3L/Tf

    Tf=307.84k

    Tf=307.84k-273k=34.84 degrees celcius

  • oliviaolivia

    Alright well this is how I did it using the Ideal Gas Law,

    first you need to find the # of moles...

    so..

    PV = nRT

    (1.48)(1.75)=n(.08206)(250.15)

    n = .12617

    and now that # of moles goes into the new scenario

    PV = nRT

    (2.073)(1.3) = (.12617)(.08206)T

    T = 260.29 K = -12.86 C

  • atlgirl8484atlgirl8484

    you need to convert to Kelvin!!!!

  • anonymousanonymous

    (1.75L) (150kPa) (1.3L)(210kPa)

    ------------------------ = ---------------------

    (250K) (xK)

    x = 260 K

    or -13C

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