HOW TO DO C PROGRAMMING?

Comments

• mason-rogers_60b60586c84a7

  June 2021

  Here is another solution.

  My predecessor used the wrong format specifier for scanf and for printf.

  That is what compelled me to re-write his code.

  The code with the error compiled and produced output; you could show it to your teacher, who in return - in a better case scenario - would point out the errors. In case you were the one who would have produced that code, you probably would have found more than one person to point out errors and this could very well have been more teaching and better than just absorbing - unreflected in the worst case scenario - a given solution and sell it as your own ... :O)

  #include <stdio.h>

  // #include <stdlib.h>

  int main()

  {

  double num1 = 0, num2 = 0, num3 = 0, num4 = 0, num5 = 0;

  printf("Please enter the 5 double numbers ");

  scanf("%lf %lf %lf %lf %lf",&num1, &num2, &num3, &num4, &num5);

  while(getchar() != '\n');

  printf("\n Sum: %.2lf"

  "\nProduct: %.2lf"

  "\nAverage: %.2lf\n", num1+num2+num3+num4+num5, num1*num2*num3*num4*num5, (num1+num2+num3+num4+num5)/5.0);

  // system("pause");

  return 0;

  }
• colm

  June 2021

  include <stdio.h>

  main()

  {

  //declare variables

  double num1 = 0;

  double num2 = 0;

  double num3 = 0;

  double num4 = 0;

  double num5 = 0;

  int sum = 0;

  int product = 0;

  int average = 0;

  //prompt user

  printf("Please enter the 5 double numbers\n");

  scanf("%d",&num1);

  scanf("%d",&num2);

  scanf("%d",&num3);

  scanf("%d",&num4);

  scanf("%d",&num5);

  //calculations

  sum = (num1+num2+num3+num4+num5);

  product = (num1*num2*num3*num4*num5);

  average = sum / 5;

  //print results

  printf("\nSum is %d",sum);

  printf("\nProduct is %d",sum);

  printf("\nAverage is %d",sum);

  }
• anonymous

  June 2021

  Okay... so... what's your question?

  Here's a simple tutorial for C

  http://www.academictutorials.com/c/