Remember that the Power Rule of Derivatives states that the derivative of a*x^n with respect to x equals: a*n*(x^(n-1)). Also, since a constant has a degree of x^0, the derivative of any constant is 0 by the Power Rule.
So, using the rule, f'(t)=(-2*2)t^(2-1) + (3*1)t^(1-1) - (0*6)x^(0-1).
Comments
Differentiate each term, using power rule d/dx xⁿ = nx^(n - 1). Remember that the derivative of the constant is 0!
f'(t) = -4t + 3
f'(x) = 1
I hope this helps!
Remember that the Power Rule of Derivatives states that the derivative of a*x^n with respect to x equals: a*n*(x^(n-1)). Also, since a constant has a degree of x^0, the derivative of any constant is 0 by the Power Rule.
So, using the rule, f'(t)=(-2*2)t^(2-1) + (3*1)t^(1-1) - (0*6)x^(0-1).
Evaluating: f'(t)= -4t+3
f'(x)= 1*x^(1-1) + 0 = 1
Therefore:
the derivative of f(t) is -4t+3
the derivative of f(x) is 1.
f(t) = -2t^2+3t-6
=> f'(t) = -2 * 2 * t + 3
=> f'(t) = -4 * t + 3
f(x)= x+1
=> f'(x) = 1