a)se log16 N= -1/2, o valor de 4N é? b) o numero real x, tal que log s (9/4)= 1/2, é?

brubru1807brubru1807
in Science & Mathematics

eu gostaria da resoluçao, nao estou consiguindo fazer!

Comments

  • arthur-white_60b5c44a5912earthur-white_60b5c44a5912e

    log 16N=-1/2

    10^-1/2=16N

    16N=1/10^1/2

    16N=1/V10

    16N=V10/10

    4N=(v10/10)/4

    4N=V10/40

    b)

    log(base x)(9/4)=1/2

    x^1/2=9/4

    (x^1/2)²=(9/4)²

    x=81/16

  • -luca-luca

    log16 N = -1/2

    N = 16^(-1/2)

    N = 1/ 16(1/2)

    N = 1/ √16

    N = 1/4

    Logo 4N = 4(1/4)

    4N = 4/4

    4N = 1

    logS 9/4 = 1/2

    S^1/2 = 9/4

    √S = 9/4

    (√S)² = (9/4)²

    S = 81/16

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