algebra word problem help?

can someone please help me with this algebra math problem i cant seem to figure it out.

find two numbers whose sum is 37 and whose difference is 21

any help is great thanks a lot

Comments

  • Call the 2 numbers are x and y, u have:

    x+y=37

    x-y=21

    ----------

    x=29

    y=8

  • Hey,

    This can be solved using the addition method in algebra.

    two numbers (x and y) that add to 37 and whose difference is 21.

    This gives you 2 equations:

    x + y = 37

    x - y = 21

    Add the two together and you'll have one equation with one variable. Solve for that variable and then use that value to help you get the other variable.

  • Make an equation, then solve for x and y.

    x+y=37

    x-y=21

    The y's cancel, and you're left with 2x=58. Divide both sides by 2, and x=29.

    Then you would plug in 29 for x to solve for y. 29+y=37 --> 37-29=8.

    Hope this helps!

  • use variables like x and y and set up two equations

    x + y = 37

    x - y = 21

    then write both in terms of y or x

    y = 37-x

    y = -21 + x

    then substitute

    37 - x = -21 + x

    -2x = -58

    x = 29

    then plug in x

    29 - y = 21

    y = 8

    so the numbers are 29 and 8

  • Assign variables to x and y

    x+y = 37

    x-y = 21

    Combine the equations and solve:

    2x = 58

    x = 58/2 = 29

    Now that you have x, plug it back in to one of the equations to get y:

    29+y = 37

    y = 37-29 = 8

    Try those numbers in both equations again to check your work.

  • 29 and 8

    take 37 and subtract 21 = 16

    take 21 and subtract 16 = 5

    you need them to be 21 in difference

    21 minus 5 is 16

    16 divided by 2 (to add half to the higher number and take half from the lower number) = 8

    21 plus 8 = 29

    16 minus 8 = 8

    29 plus 8 = 37

    29 minus 8 = 16

    There you go.

  • If the students current grade is a 90% then we’re of course assuming it’s out of 100% 90/100 Now since the students grade improved 20% from the last grading period then you add that to the previous 100% giving you 90/ 120 = .75 And since grades are in percentages you multiply .75 by 100 giving you 75% as the students previous grade

  • Set up a system of equations:

    x+y=37

    X-Y=21

    Solve one of the equations for one of the variables:

    x=37-y

    Plug that into the other equation in place of x:

    (37-y)-y=21

    Solve for y:

    37-2y=21

    y=8

    Plug this y into one of the equations and solve for x:

    X+8=37

    X=29

    There you go! Hope this helps!

  • X+Y= 37

    X-Y=21

    Adding the two equations we get

    2X =58

    X=29

    lets substitute the value of x in the first equation

    29+Y=37

    Y=37-29

    Y=8

  • (8,29)

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