asymptotes are st. lines that are tangent to the curve at infinity.
If its not in your course, just dont bother! You dont need to know atleast for this question.
This is a simple translation problem in which the co-ordinate system is moved to (1,-1) and the axex are parallel to the original.
so the answer will be, (y+1) = 2/(x-1)
if asymptotes are in your course, then you should be able to view that x=0, y=0 are asymptotes to the original equation and that x=1, y=-1 are asymptotes to the translated equation.
Comments
asymptotes are st. lines that are tangent to the curve at infinity.
If its not in your course, just dont bother! You dont need to know atleast for this question.
This is a simple translation problem in which the co-ordinate system is moved to (1,-1) and the axex are parallel to the original.
so the answer will be, (y+1) = 2/(x-1)
if asymptotes are in your course, then you should be able to view that x=0, y=0 are asymptotes to the original equation and that x=1, y=-1 are asymptotes to the translated equation.
Happy asymptoting...
asymptotes r tangents that never touch the curve.
Theoretically they touch at infinity.
ex. x=pi/2 is an asymptote to y = tanx
and I didnt get what is meant by the second part of the Qsn.
So i tried to interpret it myself;
xy=2 is a rect. Hyperbola
Asymptotes are x=0, y=0 So what i thought is maybe we have to shift the x-y axes such that x=1, y= -1 become the asymptotes;
So the required equation becomes;
(x-1)*(y+1) = 2;
y = 2/(x-1)-1;
y = (3-x)/(x-1)