Algebra problem - please help?

( 6- √6) (3√2 - 2√3) (4√2 + 3√3) / 6

√ = square root

/ = divided by

help please and show work

Comments

  • Hi,

    ( 6- √6) (3√2 - 2√3) (4√2 + 3√3) / 6 =

    ( 6- √6) (3√2 - 2√3) (4√2 + 3√3)

    ---------------------------------------------- =

    . . . . . . . . . . 6

    (18√2 - 12√3 - 3√12 + 2√18)(4√2 + 3√3)

    ---------------------------------------------------------- =

    . . . . . . . . . . 6

    (18√2 - 12√3 - 6√3 + 6√2)(4√2 + 3√3)

    ---------------------------------------------------------- =

    . . . . . . . . . . 6

    (24√2 - 18√3)(4√2 + 3√3)

    ------------------------------------- =

    . . . . . . . . 6

    6(4√2 - 3√3)(4√2 + 3√3)

    ------------------------------------- =

    . . . . . . . . 6

    (4√2 - 3√3)(4√2 + 3√3) =

    16(2) + 12√6 - 12√6 - 27 =

    32 - 27 = 5 <==ANSWER

    I hope that helps!! :-)

  • ( 6- √6) (3√2 - 2√3) (4√2 + 3√3) / 6

    = (18√2 - 12√3 - 3√12 + 2√18)(4√2 + 3√3) / 6

    = (18√2 - 12√3 - 6√3 + 6√2)(4√2 + 3√3) / 6

    = (24√2 - 18√3)(4√2 + 3√3) / 6

    = (4√2 - 3√3)(4√2 + 3√3)

    = 32 + 12√6 - 12√6 - 27

    = 5

  • ( 6- √6) (3√2 - 2√3) (4√2 + 3√3) / 6

    multply second and third brackets.

    You'll get

    ( 6- √6) (12x2 +1√2√3 - 6x3) / 6

    simplify

    ( 6- √6) (24 +1√6 - 18) / 6

    ( 6- √6) (6 +√6) / 6

    remember the rule for multiplying bimonials with the pattern (a - b) (a + b)

    ( 36 - 6) /6

    simplify

    30/6

    =5

  • = (6- √ 6) (12√ 2*√ 2 - 8√ 3*√ 2 + 9√ 2*√ 3 - 6√ 3*√ 3):6= (6- √ 6) ( 12*2 - 8√6 + 9√6 - 6*3) :6 =

    = (6- √ 6) (24 + √6 - 18 ) : 6 = (6- √ 6) (6+ √ 6) :6= (36 - 6) :6= 30 : 6 = 5

    * - MULTIPLIED

    : - DIVIDED

    hope it is correct

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