Problem: simplify -> (a^(3x+2))/(a^(4-x))
Answer: a^(4x-2)
Can someone please explain how to get this answer? Many Thanks!!!!!!!
(a^(3x+2))/(a^(4-x))
= a^(3x+2)*a^(x-4)
= a^(3x+2+x-4)
= a^(4x-2)
Sense the base numbers are both the same you just subtract one exponent by the other
So treat it as: (3x+2)-(4-x)
Then distribute the negative: 3x+2-4+x
then simplify: 4x-2
Then put it as the exponent for the original base number. a^(4x-2)
Hope this helped!
Comments
(a^(3x+2))/(a^(4-x))
= a^(3x+2)*a^(x-4)
= a^(3x+2+x-4)
= a^(4x-2)
Sense the base numbers are both the same you just subtract one exponent by the other
So treat it as: (3x+2)-(4-x)
Then distribute the negative: 3x+2-4+x
then simplify: 4x-2
Then put it as the exponent for the original base number. a^(4x-2)
Hope this helped!