Math real life problem?
In a shop there are no prices up, but if Tom is charged 2.80AED for 3 cakes and 2 cups of Tea and Andy buys 4 cakes and 4 cups of tea for 4.60AED, how much does 1 cup of tea and 1 cake cost?
In a shop there are no prices up, but if Tom is charged 2.80AED for 3 cakes and 2 cups of Tea and Andy buys 4 cakes and 4 cups of tea for 4.60AED, how much does 1 cup of tea and 1 cake cost?
Comments
Let x be the price of a cake
let y be the price of a cup of tea.
3x+2y=2.80
4x+4y=4.60
Divide the bottom equation by -2
-2x-2y=-2.30
Add it to the first equation
3x+2y=2.80
-2x-2y=-2.30
__________
x=.50
Plug that in and find y
3(.50)+2y=2.80
1.50+2y=2.80
2y=1.30
y=.65
Cake is .50
Tea is .65
Check the answer
3(.50)+2(.65)=2.80
4(.50)+4(.65)=4.60
"Tom is charged 2.80 for 3 cakes and 2 cups of Tea"
Let c and t be the prices for a cake and a cup of tea, respectively.
3c + 2t = 2.80
"Andy buys 4 cakes and 4 cups of tea for 4.60"
4c + 4t = 4.60
Solve the system for c and t.
Note that B's answer is incorrect. Cake and tea must cost less than 1AED each.
c = 0.50AED
t = 0.65AED
Cake is 1.07 tea is 1.05