partial derivative problem?

if f(x,y) = ln(x/y) then find xf_x - y^2f_yy

hard to type it but it is xf subscript x - y^2 f subscript yy

as in the partial derivative of f with respect to x

and the partial derivative of f with respect to y done twice

Comments

  • Rewrite f as f(x,y) = ln x - ln y.

    So, f_x = 1/x and f_y = -1/y

    ==> f_xx = -1/x^2, f_yy = 1/y^2, and f_xy = 0.

    Hence,

    x f_x - y^2 f_yy = x * (1/x) - y^2 * (1/y^2) = 1 - 1 = 0.

    I hope this helps!

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