how do you simplify this problem?

how do you simplify

(t+8)(6(3t-9)^5)-(3t-9)^6 / (t+8)^2

Comments

  • (t+8)(6(3t-9)^5) - (3t-9)^6 / (t+8)^2

    At first I assumed you meant the (t+8)^2 at the end to be the denominator for the entire term, but then I decided you must mean that only the second term is divided by (t+8)^2. Too bad, because it was easier the other way.

    You have the term (t+8)^2 in the denominator of one term. You want to remove that, so factor out (t+8)^(-2) from both terms, leaving you with

    (t+8)^3(6(3t-9)^5) - (3t-9)^6

    --------------------------------------

    (t+8)^2

    Then, you can observe that you have the term (3t-9)^5 in both parts of the numerator, so you can factor that out.

    (3t-9)^5 * [((t+8)^3)6 - (3t-9)]

    ---------------------------------------

    (t+8)^2

    Then we factor some 3s out of the numerator to get

    3^5 * (t-3)^5 * 3 * [((t+8)^3)2- (t-3)]

    ------------------------------------------------

    (t+8)^2

    Let's look at the messy term [((t+8)^3)2- (t-3)].

    (t+8)(t+8)(t+8)2 - t + 3

    = (t^2 + 16t + 64)(t+8)2 - t + 3

    = (t^3 + 16t^2 + 64t + 8t^2 + 128t + 512)2 - t + 3

    = (t^3 + 24t^2 + 192t + 512)2 - t + 3

    That part doesn't simplify very well unfortunately.

    I hope you can perform the remaining multiplication and addition, substitute, and finish the problem from there. It's best not to do someone else's homework completely for them. ;)

  • (t+8)(6(3t-9)^5)-(3t-9)^6 / (t+8)^2

    (t+8)(6(3^5t^5-9^5)-(3^6*t^6-9^6)/(t^2+8^2)

    (t+8)(6*3^5*6t^5-6*9^5) - (3^6*t^4-9^6)/8^2)

    8(6*3^5*6t^6-6t*9^5) -8^2*3^6*t^4 -9^6*8^2

    48*3^5*6t^6-48t*9^5 -8^2*3^6*t^4 -9^6*8^2

    69984t^6 - 2834352t - 46656t^4 - 34012224

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