Qual o resultado da equação x/2 - (x-1/3) + 17/12 = x + (x+7/4)?

Comments

• maria-descartes

  May 2021

  Veja:

  x/2 - (x-1/3) + 17/12 = x + (x+7/4)

  x/2 - x+1/3+ 17/12 = x +x+7/4

  (6x-12x+4+17)/12=(12x+12x+21)/12

  (6x-12x+4+17)=(12x+12x+21)

  -6x+21=24x+21

  24x+6x=21-21

  30x=0

  x=0
• caraduradepau

  May 2021

  x/2-(x-1/3)+17/12=x+(x+7/4)

  x/2-(3x-1/3)+17/12=x+(4x+7/4) mmc2,3,4,12=12

  6x-12x+4+17=12x+12x+21

  -6x-24x=21-21

  -30x=0

  x=0
• fabiola-marielly

  May 2021

  Veja:

  x/2 - (x-1/3) + 17/12 = x + (x+7/4) mmc {12, 3, 4}= 12

  x/2 - x+1/3+ 17/12 = x +x+7/4

  (6x-12x+4+17)/12=(12x+12x+21)/12

  (6x-12x+4+17)=(12x+12x+21)

  -6x+21=24x+21

  24x+6x=21-21

  30x=0

  x=0/30

  x=0

  Espero ter ajudado...BjO
• neydehenriques

  May 2021

  x/2-(3x-1)/3+17/12=x+(4x+7)/4 mmc=12

  6x-(12x-4)+17 =12x+(12x+21)

  6x-12x+4+17=12x+12x+21

  -6x+21=24x+21

  -6x-24x=0

  -30x=0

  x=0