percentage problem for a math quiz?
In 2001, the population in a town was 11% more than it was in 2000. If the population was 27,910 in 2002, which was 10% more than 2001, find the population in 2000.
I have done this problem and keep getting the answer 22356. Please tell me what I am doing wrong and how to fix it. Big math exam tomorrow. Need to get a good quiz warm up grade.
Comments
Say the population in 2000 was x,
2000: (x)
2001: (1.11x) [11% more than in 2000)
2002:(1.221x) [10% more than in 2001)
So,
1.221x = 27,910
x = 27,910/1.221
x = ~22,858...population in 2000
Let's say that the population in 2000 is 100
so in 2001 it is 100+11 ok? that makes 111
and in 2002 it is 111+11,1 ok? that makes 122.1
so to find the population back in 2000 we must say
simply if the 100 became 122.1
then x? for the 27,910
x=(100x27,910)/122.1=22,858
and we can make it certain by calculating vice versa
22,858+2,515(11%)=25,373+2,537(10%)=27910
I hope I have helped you
Angela
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