Algebra Problem!!!!........Please HELP!?!!?

Comments

• ranjankar

  May 2021

  Let pan pizza be x calories

  beef buritto be y calories

  x + 2y = 1980

  2x + y = 2670

  Multiply equation 2 by 2

  4x + 2y = 5340

  x + 2y = 1980

  SUBTRACT

  3x = 5340 - 1980 = 3360

  x = 1120 calories

  y = 430 calories

  ANSWER Pan pizza 1120 calories Burritto 430 calories
• zachary-griffiths_60b27ec41acb0

  May 2021

  lets say pizza is x, and beef burritos is y. You then set up two equations to solve, one for each sentence with information.

  x + 2y = 1980

  2x + y = 2670

  then set one of the equations equal to one variable and use the substitution method to solve.

  x = -2y + 1980

  2(-2y + 1980) + y = 2670

  -4y + 3960 + y = 2670

  -3y + 3960 = 2670

  -3y = -1290

  y = 430

  so each beef burrito has 430 calories, and you substitute that value into an original equation to find the pizza.

  x + 2(430) = 1980

  x + 860 = 1980

  x = 1120

  so each pan pizza has 1120 calories, and each beef burrito has 430 calories.
• pinkypratima03

  May 2021

  Let pan pizza provide 'p' calories and beef burrito provide 'b' calories

  therefore 1 p + 2 b = 1980

  and 2p + 1 b = 2670

  i.e 3p + 3b = 4650

  p+b= 1550

  p= 1550-b

  now 1550 -b +2b= 1980

  therefore b = 430

  and p = 1120

  The calorific value of pizza is 1120 cal while that of beef burritos is 430 calories
• oana-v

  May 2021

  p=pan pizza

  b=beef burritos

  1p+2b=1980

  2p+1b=2670

  -2p-4b=-3960

  2p+1b=2670

  -3b=-1290

  one beef burrito provide 430 calories

  one pan pizza provide 1120 calories
• jeremy-mason_60b27ec63ed40

  May 2021

  No one used matrices to solve this, ah well