Num triangulo retangulo,temos cos x = raiz quadrada de 3/2,sendo x um angulo agudo desse triangulo.?

Comments

• pedro-rodrigues

  May 2021

  sen² x + cos² x = 1

  sen² x + (√3/2)² = 1

  sen² x + 3/4 = 1

  sen² x = 1 - 3/4 m.m.c = 4

  sen x = √1/4

  senx = 1/2.

  tg x = sen x / cos x

  tg x = 1/2 / √3/2

  tg x = 1/2 . 2/√3

  tg x = 2/2√3 = 1/√3 , racionaliza:

  tg x = √3/3.