Math problems (2a2-3a+a)+(5a-5)?
hello there, can someone solve this problem please.
and it was (2a squared-3a+a)+(5a-5)
please help.
Update:i can't figured it out how to put squared, so its like this. (2a^-3a+a)+(5a-5)
hello there, can someone solve this problem please.
and it was (2a squared-3a+a)+(5a-5)
please help.
Update:i can't figured it out how to put squared, so its like this. (2a^-3a+a)+(5a-5)
Comments
(2a^2 - 3a + a) + (5a - 5)
= 2a^2 - 3a + a + 5a - 5
= 2a^2 - 2a + 5a - 5
= 2a^2 + 3a - 5
a million. First, subtract the 7 to get it to the different section and performance 2m on my own. 21=7-2m -----D 14=2m Then, divide via two to get m on my own. 14=2m --------D 14/2=2m/2 ------D 7=M M=7 2. Subtrace the 5. -3m=-9 Divide via -3 now. -3m/-3=-9/-3 ----D m=-3 m=-3 3. similar recurring with something. This time upload the 16 notwithstanding when you consider that its a negitive. -7x-16=21 -7x=37 -7x/-7=37/-7 X=-5.3 4. -2y+27=39 -2y=12 y=-6 5. -3-3x=-2 upload the three. -3x=a million x=-3