Ideal gas problem - Chemistry problem?
R = 8.314510 L kPa / mol K
How many times more pressure is required to compress a 1.0 L sample of a gas measured at -20 degrees C to a final volume ot 0.50 L measured at 40.0 degrees C?
R = 8.314510 L kPa / mol K
How many times more pressure is required to compress a 1.0 L sample of a gas measured at -20 degrees C to a final volume ot 0.50 L measured at 40.0 degrees C?
Comments
you are looking for a ratio of new P to old P
P1 / Po = (nRT/V)_1 / (nRT/V)_o
n and R do not change so they cancel
T1 = 313 K and To = 253 K
P1/Po = (313/0.50) / (253/1.0) = 2.47/1 or about 2 1/2 times
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P1V1/T1 = P2V2/T2
P1 = 1
V1 = 1.0 L
T1 = 253.15 K
P1V1/T1 = 0.003950
P2 = ?
V2 = 0.50 L
T2 = 313.15 K
P2V2/T2 = P2 x 0.001597
0.003950 = P2 x 0.001597
P2 = 2.47
P2 = 2.47 x P1
PV=nRT
do T in K = C+273