Like the other person said, if you can see an obvious factor, then go ahead and try to factor the equation out by multiplying the first coefficient by the last number and find two digits that multiply to be that number and add to be the middle number. In this case, you would multiply 4 by 201 to get 804. You would then try to find two numbers that multiply to get 804 and add to get -20. There aren't any easy ways to get this without pulling out the calculator, so that means that you are going to have to use the quadratic formula. I'm pretty sure you know what that is, but lets review anyway, shall we?
Here's the basic equation for a quadratic equation:
AX^2 + BX + C
To find the solutions, use the equation
(-B +or- squareroot(B^2-4AC))/2A
For your equation, this would be
(20 * squareroot(400-3216)/8
Uh oh, you got a -2816 under the square root. That means that the equation is undefined. This means that the quadratic wquation "4x^2-20x+201" has no x-intercepts.
Comments
Like the other person said, if you can see an obvious factor, then go ahead and try to factor the equation out by multiplying the first coefficient by the last number and find two digits that multiply to be that number and add to be the middle number. In this case, you would multiply 4 by 201 to get 804. You would then try to find two numbers that multiply to get 804 and add to get -20. There aren't any easy ways to get this without pulling out the calculator, so that means that you are going to have to use the quadratic formula. I'm pretty sure you know what that is, but lets review anyway, shall we?
Here's the basic equation for a quadratic equation:
AX^2 + BX + C
To find the solutions, use the equation
(-B +or- squareroot(B^2-4AC))/2A
For your equation, this would be
(20 * squareroot(400-3216)/8
Uh oh, you got a -2816 under the square root. That means that the equation is undefined. This means that the quadratic wquation "4x^2-20x+201" has no x-intercepts.
Wow what a waste of time right?
4x^2 + 20x +25 product =(25 *4) =a hundred sum= 20 factor = (10,10) ; i.e (10*10=a hundred and 10+10=20) then u destroy the 20x hence 4x^2 + 10x +10x +25 eliminate commons 2x (2x + 5) + 5x (2x + 5) (2x + 5) (2x + 5) this equipment might properly be executed for any kind trinomial..yet u shud be speedy in looking the factors...hp u understand..:D
Try factoring it as a complex trinomial so:
Find two numbers that multiply to 804 and add to -20.
Then, rewrite the first term without exponent ad using the factors you found.
Divide out the common factor for each bracketted binomial.