4x^3-8x^2-25x+50
I can't figure out or remember how to do this. I know that this is done in pieces, but i don't know where to start! Help!
factor out 4x^2 from fist two terms and -25 from last two terms
then it will become
4x^2(x - 2) - 25(x - 2)
now factor out x - 2
(x - 2)(4x^2 - 25)
these are the factors of given polynomial
use grouping
(4x^3-8x^2)-(25x+50)
factor
4x^2(x-2)-25(x-2)
(4x^2-25)(x-2)
you can expand (4x^2-25)
a^2-b^2=(a+b)(a-b)
(2x)^2-5^2
(2x+5)(2x-5)
answer: (2x+5)(2x-5)(x-2).
4x^3-8x^2-25x+50=
(4x^3-8x^2)-(25x-50)=
4x(2x-2)-25(x-2)=
(x-2)(4x-25)
Comments
factor out 4x^2 from fist two terms and -25 from last two terms
then it will become
4x^2(x - 2) - 25(x - 2)
now factor out x - 2
(x - 2)(4x^2 - 25)
these are the factors of given polynomial
use grouping
(4x^3-8x^2)-(25x+50)
factor
4x^2(x-2)-25(x-2)
(4x^2-25)(x-2)
you can expand (4x^2-25)
a^2-b^2=(a+b)(a-b)
(2x)^2-5^2
(2x+5)(2x-5)
answer: (2x+5)(2x-5)(x-2).
4x^3-8x^2-25x+50=
(4x^3-8x^2)-(25x-50)=
4x(2x-2)-25(x-2)=
(x-2)(4x-25)
(4x^2-25)(x-2)