Algebra Problem: If x^2 = y + z, y^2 = z + x, z^2 = x + y?

If x^2 = y + z, y^2 = z + x, z^2 = x + y

then find the value of (1/x+1) + (1/y+1) + (1/z+1)

Comments

  • x^2 = y + z, y^2 = z + x, z^2 = x + y

    or,x^2+x=y+z+x, y^2+y=z+x+y, z^2+z=x+y+z

    i.e,x(x+1)=x+y+z, y(y+1)=x+y+z, z(z+1)=x+y+z ...(i)

    Now,

    (1/x+1) + (1/y+1) + (1/z+1)

    =1/(x+1) + 1/(y+1) + 1/(z+1)

    =x/[x(x+1)] + y/[y(y+1)] + z/[z(z+1)]

    =x/(x+y+z) + y/(x+y+z) + z/(x+y+z) ( using (i) )

    =(x+y+z)/(x+y+z) ( on simplifying )

    =1 ( <= Answer)

  • x^2 = y + z, y^2 = z + x, z^2 = x + y

    The above three equalities are of similar

    nature and can be true only if x = y = z

    =>x^2 = x + x

    =>x(x - 2) = 0

    =>x = 0 and 2

    =>x = y = z = 0 and 2

    1/x+1 + 1/y+1 + 1/z+1

    I) when x=y=z=0

    = 1+1+1 = 3

    II) when x=y=z=2

    = 1/3+1/3+1/3 = 1

  • If x^2 = y + z, y^2 = z + x, z^2 = x + y

    x^2 + y^2 + z^2 = 2(x + y + z)

    (1/x+1) + (1/y+1) + (1/z+1) = 9/2

  • endure in techniques this form of the equation of a airplane. we've 3 unknowns in the final sort. z=ax+by using+c the place a, b, and c are constants. we've 3 factors, so we are able to write 3 equations to unravel for a,b and c factors are (-a million/2,0,0), (0,-4/3,0), and (0,0,-5/8) shall we write those equations a million) 0=-a million/2a+0b+c 2) 0=0a-4/3b+c 3) -5/8=0a+0b+c from 3) all of us be attentive to that c=-5/8 Plug this cost right into a million) and a pair of) and resolve for a and b respectively. 0=-a million/2 a - 5/8 a=-10/8=-5/4 0=-4/3b - 5/8 b=-15/32 the airplane is z= -5/4 a - 15/32 b - 5/8

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