(15/7a)(14/3b)=
2(3r+4)=5(-2r-8)=
2(3r+1)+6=5(-2r-8)=
1. Just multiply across and reduce.
(15/7a)(14/3b) = 210/21ab = 10ab
2. Distribute the numbers outside of the parentheses.
2(3r+4)=5(-2r-8)
(2*3r)+(2*4) = (5*-2r)-(5*8)
6r+8=-10r-40
16r = -48
r = -3
3. Same thing as #2.
2(3r+1)+6=5(-2r-8)
(2*3r)+(2*1)+6 = (5*-2r)-(5*8)
6r+2+6 = -10r - 40
you can also try hotmath.com
you just click on your math book, and the page number, and they have most of the odd problems
1). (10/ab)
2). r = -3
3). r = -3
Check out
http://www.myalgebra.com/
You can get all your problems solved quick and easy
Comments
1. Just multiply across and reduce.
(15/7a)(14/3b) = 210/21ab = 10ab
2. Distribute the numbers outside of the parentheses.
2(3r+4)=5(-2r-8)
(2*3r)+(2*4) = (5*-2r)-(5*8)
6r+8=-10r-40
16r = -48
r = -3
3. Same thing as #2.
2(3r+1)+6=5(-2r-8)
(2*3r)+(2*1)+6 = (5*-2r)-(5*8)
6r+2+6 = -10r - 40
6r+8=-10r-40
16r = -48
r = -3
you can also try hotmath.com
you just click on your math book, and the page number, and they have most of the odd problems
1). (10/ab)
2). r = -3
3). r = -3
Check out
http://www.myalgebra.com/
You can get all your problems solved quick and easy