math word problem....?
1. The period P of a simple pendulum - that is, the time required for one complete oscillation - is directly proportional to the square root of its length l. Express P in terms of l and a constant of proportionality k. If a pendulum 2.4 feet long has a period of 1.4 seconds, find the value of k.
Give the answer correct to two decimal places.
k=?
Comments
P = k * sqrt(length)
Substitute length=2.4, P=1.4
1.4 = k * sqrt(2.4)
k = 1.4 / sqrt(2.4), which you can do with a calculator.
The equation is P = k * sqrt(l)
To solve for k, plug in the values given for P and l:
1.4 = k * sqrt(2.4)
Take the square root of 2.4:
1.4 = k * 1.55
Divide both sides by 1.55:
k = 1.4 / 1.55
k = 0.71
If something is 40% smaller, you purely subtract 40%. So 40% of 40 energy is sixteen: you are attempting this via multiplying 40 via 0.4. the respond could be 40 - sixteen = 24 A shorter way could in basic terms be to multiply via 40 via 0.6, for the reason that this could be a million-0.4.
qaure root of 2.4?
wow. Now I remember why I never made it past pre algebra ...
Best wishes!
think simple algebra