The length of a table is 4 cm more than its width.Its area is 117 cm2.Find its dimensions.
(x)(x+4) = 117
x^2 + 4x = 117
x^2 + 4x -117 = 0
(x+13)(x-9) = 0
since you cant have a negative length, x = 9 and x+4 = 13
9x13 = 117
the equation is:
w(w+4)= 117. didtribute:
w^2+4w=117. turns into:
w^2+4w-117=0
factor. find the roots. pick the positive one as width. add 4 to that for length and check.BAM
pretty good for a going on eight grader, huh?
the equation would be
x(x+4) = 117
x2 +4 = 117
-4 -4
x2= 113
square root of x2 = square root of 113
x= 10.63
length is equal to 14.63
width is equal to 10.63
square root of 29.25
equation- 4x * x = 117
why are you still in school? ahah
Comments
(x)(x+4) = 117
x^2 + 4x = 117
x^2 + 4x -117 = 0
(x+13)(x-9) = 0
since you cant have a negative length, x = 9 and x+4 = 13
9x13 = 117
the equation is:
w(w+4)= 117. didtribute:
w^2+4w=117. turns into:
w^2+4w-117=0
factor. find the roots. pick the positive one as width. add 4 to that for length and check.BAM
pretty good for a going on eight grader, huh?
the equation would be
x(x+4) = 117
x2 +4 = 117
-4 -4
x2= 113
square root of x2 = square root of 113
x= 10.63
length is equal to 14.63
width is equal to 10.63
square root of 29.25
equation- 4x * x = 117
why are you still in school? ahah