Algebra word problems?
Update:
A women's soccer team played its inaugural season at Stadium A. The perimeter of the soccer field is 370370 yards. If the length is 4040 yards less than twice the width, what are the dimensions of the field?
The team played on a field that was ___ yards long and ____ yards wide.
Comments
A women's soccer team played its inaugural season at Stadium A.
The perimeter of the soccer field is 370 yards.
If the length is 40 yards less than twice the width, what are the dimensions of the field?
The team played on a field that was ___ yards long and ____ yards wide.
P = 2L + 2W
370 = 2L + 2W
L = 2W - 40
The length is 40 yards less than 2 times the width.
Make a system:
370 = 2L + 2W
L = 2W - 40
Substitute L for 2W - 40 in the original equation.
Then simplify and solve for W:
370 = 2(2W - 40) + 2W
370 = 4W - 80 + 2W
370 = 6W - 80
+80 + 80
450 = 6W
75 = W
Substitute 75 for W into one of the equations and solve for L:
L = 2(75) - 40
L = 150 - 40
L = 110
Dimensions are L = 110 yds and W = 75 yds.