two numbers have a difference of 10 and the sum of 34. what are the numbers?
a+b=34
a-b=10
2a +b-b = 44
2a = 44
a = 22
b = 34-22 = 12
The two numbers, 22 and 12
Hard to believe that this is 5th grade math.
Call the numbers a and b:
a - b = 10 [they're different by 10]
a + b = 34 [their sum is 34]
You can add the equations to eliminate the b term:
a - b = 10
+(a + b = 34)
---------------
Divide both sides by 2:
Put 22 into either original equation to solve for b:
22 + b = 34
Subtract 22 from both sides:
b = 12
The numbers are 22 and 12.
12 and 22
12, 22
Comments
a+b=34
a-b=10
2a +b-b = 44
2a = 44
a = 22
b = 34-22 = 12
The two numbers, 22 and 12
Hard to believe that this is 5th grade math.
Call the numbers a and b:
a - b = 10 [they're different by 10]
a + b = 34 [their sum is 34]
You can add the equations to eliminate the b term:
a - b = 10
+(a + b = 34)
---------------
2a = 44
Divide both sides by 2:
a = 22
Put 22 into either original equation to solve for b:
22 + b = 34
Subtract 22 from both sides:
b = 12
The numbers are 22 and 12.
12 and 22
12, 22