The double integral goes from (outer)[0,1] and the (inner)[0,x]. Please help!!
∫_[0,1] {∫_[0,x] cos(x²) dy} dx
= ∫_[0,1] {ycos(x²) |_[y=0,x]} dx
= ∫_[0,1] xcos(x²) dx
= ½sin(x²) |_[x=0,1]
= ½sin(1)
Comments
∫_[0,1] {∫_[0,x] cos(x²) dy} dx
= ∫_[0,1] {ycos(x²) |_[y=0,x]} dx
= ∫_[0,1] xcos(x²) dx
= ½sin(x²) |_[x=0,1]
= ½sin(1)