If DE= x+y, EC=12, CK=2x-y, and KD=3x-2y, the x= blank and y= blank and the perimeter of DECK= blank
please help
x+y=2x-y
x=2y
3x-2y=12
3(2y)-2y=12
4y=12
y=3
x=6
Perimeter = DE+EC+CK+KD=9+12+9+12=42
Opposite sides in parallelograms are equal.
We can set up the following equations.
Then we simplify both leaving...
3x=12+2y
x=(12+2y)/3
Plug in 2y for x in the first equation.
2y=(12+2y)/3
6y=12+2y
Plug 3 into the first equation.
3x=12+2(3)
The perimeter can be found by plugging in x and y into the other equations for the sides.
x=6 and y=3
Good Luck!
Comments
x+y=2x-y
x=2y
3x-2y=12
3(2y)-2y=12
4y=12
y=3
x=6
Perimeter = DE+EC+CK+KD=9+12+9+12=42
Opposite sides in parallelograms are equal.
We can set up the following equations.
3x-2y=12
x+y=2x-y
Then we simplify both leaving...
3x=12+2y
x=(12+2y)/3
x=2y
Plug in 2y for x in the first equation.
2y=(12+2y)/3
6y=12+2y
y=3
Plug 3 into the first equation.
3x=12+2(3)
x=6
The perimeter can be found by plugging in x and y into the other equations for the sides.
x=6 and y=3
Good Luck!