Infinite Series Calc Help?

Having trouble figure out this problem!! It says:

Find the sum of the series sum (n=1 to infinity) 1/(n^5) correct to three decimal places.

I need to know how to do it, not just an answer! I missed a couple classes due to illness when this was explained and now I'm in the dark. :(

Update:

I do not know how to solve it but I'm at least positive that isn't it, Vikram. Sorry!

Comments

  • infinite series sum in GP is a/(1-r)

    S = 1/5 + 1/25 + 1/ 125 + 1/625 .... inf

    = (1/5)/(1-1/5) = 1/4 = 0.250

  • a geometrical sequence has a set ratio between consecutive words. a available sequence does not. Restated, a geometrical sequence will be seen as particular case of a available sequence the position the finished sequence is sped up by some consistent a and human being words have a coefficient of one million. Geometric: y = a? a million + x^2 + x^3 + x^4 + . . .x^n skill: y = ? a + bx^2 + cx^3 + dx^4 + . . .?x^n, the position ? represents the nth coefficient.

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